(16x)^2-18x-55=0

Solution for (16x)^2-18x-55=0 equation:

(16x)^2-18x-55=0

a = 16; b = -18; c = -55;
Δ = b2-4ac
Δ = -182-4·16·(-55)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-62}{2*16}=\frac{-44}{32}
=-1+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+62}{2*16}=\frac{80}{32}
=2+1/2
$